(3x+2)/9=(2x-5)/8

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Solution for (3x+2)/9=(2x-5)/8 equation: 



(3x+2)/9=(2x-5)/8

We move all terms to the left:

(3x+2)/9-((2x-5)/8)=0

We calculate fractions


3x/()+(-((2x-5)*9)/()=0



We calculate terms in parentheses: +(-((2x-5)*9)/(), so:

-((2x-5)*9)/(

We multiply all the terms by the denominator


-((2x-5)*9)



We calculate terms in parentheses: -((2x-5)*9), so:

(2x-5)*9

We multiply parentheses

18x-45

Back to the equation:

-(18x-45)



We get rid of parentheses

-18x+45

Back to the equation:

+(-18x+45)



We get rid of parentheses

3x/()-18x+45=0

We multiply all the terms by the denominator


3x-18x*()+45*()=0

We add all the numbers together, and all the variables

3x-18x*()=0

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