(3x+2)/2=(3+8x)/3

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Solution for (3x+2)/2=(3+8x)/3 equation: 



(3x+2)/2=(3+8x)/3

We move all terms to the left:

(3x+2)/2-((3+8x)/3)=0

We add all the numbers together, and all the variables

(3x+2)/2-((8x+3)/3)=0

We calculate fractions


3x/()+(-((8x+3)*2)/()=0



We calculate terms in parentheses: +(-((8x+3)*2)/(), so:

-((8x+3)*2)/(

We multiply all the terms by the denominator


-((8x+3)*2)



We calculate terms in parentheses: -((8x+3)*2), so:

(8x+3)*2

We multiply parentheses

16x+6

Back to the equation:

-(16x+6)



We get rid of parentheses

-16x-6

Back to the equation:

+(-16x-6)



We get rid of parentheses

3x/()-16x-6=0

We multiply all the terms by the denominator


3x-16x*()-6*()=0

We add all the numbers together, and all the variables

3x-16x*()=0

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