(3x+2)/2+(4x+5)/4-(3x-8)/8=16

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Solution for (3x+2)/2+(4x+5)/4-(3x-8)/8=16 equation: 



(3x+2)/2+(4x+5)/4-(3x-8)/8=16

We move all terms to the left:

(3x+2)/2+(4x+5)/4-(3x-8)/8-(16)=0

We calculate fractions

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