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(3x+2)/(2x-3)=3/5
We move all terms to the left:
(3x+2)/(2x-3)-(3/5)=0
Domain of the equation: (2x-3)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
2x!=3
x!=3/2
x!=1+1/2
x∈R
(3x+2)/(2x-3)-(+3/5)=0
We get rid of parentheses
(3x+2)/(2x-3)-3/5=0
We calculate fractions
(15x+10)/(10x-15)+(-6x+9)/(10x-15)=0
We multiply all the terms by the denominator
(15x+10)+(-6x+9)=0
We get rid of parentheses
15x-6x+10+9=0
We add all the numbers together, and all the variables
9x+19=0
We move all terms containing x to the left, all other terms to the right
9x=-19
x=-19/9
x=-2+1/9
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