(3x+2)-4(x-2)=4(x-5)+3(2x-1)

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Solution for (3x+2)-4(x-2)=4(x-5)+3(2x-1) equation: 



(3x+2)-4(x-2)=4(x-5)+3(2x-1)

We move all terms to the left:

(3x+2)-4(x-2)-(4(x-5)+3(2x-1))=0

We multiply parentheses

(3x+2)-4x-(4(x-5)+3(2x-1))+8=0

We get rid of parentheses

3x-4x-(4(x-5)+3(2x-1))+2+8=0



We calculate terms in parentheses: -(4(x-5)+3(2x-1)), so:

4(x-5)+3(2x-1)

We multiply parentheses

4x+6x-20-3

We add all the numbers together, and all the variables

10x-23

Back to the equation:

-(10x-23)



We add all the numbers together, and all the variables

-1x-(10x-23)+10=0

We get rid of parentheses

-1x-10x+23+10=0

We add all the numbers together, and all the variables

-11x+33=0

We move all terms containing x to the left, all other terms to the right

-11x=-33

x=-33/-11

x=+3

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