(3x+2)+6x=(12x-31)

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Solution for (3x+2)+6x=(12x-31) equation: 



(3x+2)+6x=(12x-31)

We move all terms to the left:

(3x+2)+6x-((12x-31))=0

We add all the numbers together, and all the variables

6x+(3x+2)-((12x-31))=0

We get rid of parentheses

6x+3x-((12x-31))+2=0



We calculate terms in parentheses: -((12x-31)), so:

(12x-31)

We get rid of parentheses

12x-31

Back to the equation:

-(12x-31)



We add all the numbers together, and all the variables

9x-(12x-31)+2=0

We get rid of parentheses

9x-12x+31+2=0

We add all the numbers together, and all the variables

-3x+33=0

We move all terms containing x to the left, all other terms to the right

-3x=-33

x=-33/-3

x=+11

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