(3x+2)+(7y+1)=140

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Solution for (3x+2)+(7y+1)=140 equation:


Simplifying
(3x + 2) + (7y + 1) = 140

Reorder the terms:
(2 + 3x) + (7y + 1) = 140

Remove parenthesis around (2 + 3x)
2 + 3x + (7y + 1) = 140

Reorder the terms:
2 + 3x + (1 + 7y) = 140

Remove parenthesis around (1 + 7y)
2 + 3x + 1 + 7y = 140

Reorder the terms:
2 + 1 + 3x + 7y = 140

Combine like terms: 2 + 1 = 3
3 + 3x + 7y = 140

Solving
3 + 3x + 7y = 140

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + 3x + -3 + 7y = 140 + -3

Reorder the terms:
3 + -3 + 3x + 7y = 140 + -3

Combine like terms: 3 + -3 = 0
0 + 3x + 7y = 140 + -3
3x + 7y = 140 + -3

Combine like terms: 140 + -3 = 137
3x + 7y = 137

Add '-7y' to each side of the equation.
3x + 7y + -7y = 137 + -7y

Combine like terms: 7y + -7y = 0
3x + 0 = 137 + -7y
3x = 137 + -7y

Divide each side by '3'.
x = 45.66666667 + -2.333333333y

Simplifying
x = 45.66666667 + -2.333333333y

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