(3x+2)(x-5)(2x+15)=6(x+2)

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Solution for (3x+2)(x-5)(2x+15)=6(x+2) equation: 



(3x+2)(x-5)(2x+15)=6(x+2)

We move all terms to the left:

(3x+2)(x-5)(2x+15)-(6(x+2))=0

We multiply parentheses ..

(+3x^2-15x+2x-10)(2x+15)-(6(x+2))=0



We calculate terms in parentheses: -(6(x+2)), so:

6(x+2)

We multiply parentheses

6x+12

Back to the equation:

-(6x+12)



We get rid of parentheses

(+3x^2-15x+2x-10)(2x+15)-6x-12=0

We move all terms containing x to the left, all other terms to the right

(+3x^2-15x+2x-10)(2x+15)-6x=12

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