(3x+2)(x-4)(x)=2

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Solution for (3x+2)(x-4)(x)=2 equation: 


Simplifying
(3x + 2)(x + -4)(x) = 2

Reorder the terms:
(2 + 3x)(x + -4)(x) = 2

Reorder the terms:
(2 + 3x)(-4 + x)(x) = 2

Reorder the terms for easier multiplication:
x(2 + 3x)(-4 + x) = 2

Multiply (2 + 3x) * (-4 + x)
x(2(-4 + x) + 3x * (-4 + x)) = 2
x((-4 * 2 + x * 2) + 3x * (-4 + x)) = 2
x((-8 + 2x) + 3x * (-4 + x)) = 2
x(-8 + 2x + (-4 * 3x + x * 3x)) = 2
x(-8 + 2x + (-12x + 3x2)) = 2

Combine like terms: 2x + -12x = -10x
x(-8 + -10x + 3x2) = 2
(-8 * x + -10x * x + 3x2 * x) = 2
(-8x + -10x2 + 3x3) = 2

Solving
-8x + -10x2 + 3x3 = 2

Solving for variable 'x'.

Reorder the terms:
-2 + -8x + -10x2 + 3x3 = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + -8x + -10x2 + 3x3 = 0

The solution to this equation could not be determined.

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