(3x+2)(x+3)=286

Solution for (3x+2)(x+3)=286 equation:

(3x+2)(x+3)=286

We move all terms to the left:

(3x+2)(x+3)-(286)=0

We multiply parentheses ..

(+3x^2+9x+2x+6)-286=0

We get rid of parentheses

3x^2+9x+2x+6-286=0

We add all the numbers together, and all the variables

3x^2+11x-280=0

a = 3; b = 11; c = -280;
Δ = b2-4ac
Δ = 112-4·3·(-280)
Δ = 3481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3481}=59$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-59}{2*3}=\frac{-70}{6}
=-11+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+59}{2*3}=\frac{48}{6}
=8
$