(3x+2)(x+1)=3x2+17

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Solution for (3x+2)(x+1)=3x2+17 equation: 



(3x+2)(x+1)=3x^2+17

We move all terms to the left:

(3x+2)(x+1)-(3x^2+17)=0

We get rid of parentheses

-3x^2+(3x+2)(x+1)-17=0

We multiply parentheses ..

-3x^2+(+3x^2+3x+2x+2)-17=0

We get rid of parentheses

-3x^2+3x^2+3x+2x+2-17=0

We add all the numbers together, and all the variables

5x-15=0

We move all terms containing x to the left, all other terms to the right

5x=15

x=15/5

x=3

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