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(3x+2)(9x+2)=0
We multiply parentheses ..
(+27x^2+6x+18x+4)=0
We get rid of parentheses
27x^2+6x+18x+4=0
We add all the numbers together, and all the variables
27x^2+24x+4=0
a = 27; b = 24; c = +4;
Δ = b2-4ac
Δ = 242-4·27·4
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-12}{2*27}=\frac{-36}{54} =-2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+12}{2*27}=\frac{-12}{54} =-2/9 $
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