(3x+19)+(6x-2)=180

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Solution for (3x+19)+(6x-2)=180 equation: 



(3x+19)+(6x-2)=180

We move all terms to the left:

(3x+19)+(6x-2)-(180)=0

We get rid of parentheses

3x+6x+19-2-180=0

We add all the numbers together, and all the variables

9x-163=0

We move all terms containing x to the left, all other terms to the right

9x=163

x=163/9

x=18+1/9

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