(3x+19)+(3x+4)=10x-1

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Solution for (3x+19)+(3x+4)=10x-1 equation: 



(3x+19)+(3x+4)=10x-1

We move all terms to the left:

(3x+19)+(3x+4)-(10x-1)=0

We get rid of parentheses

3x+3x-10x+19+4+1=0

We add all the numbers together, and all the variables

-4x+24=0

We move all terms containing x to the left, all other terms to the right

-4x=-24

x=-24/-4

x=+6

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