(3x+19)+(2x+22)=5x+41

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Solution for (3x+19)+(2x+22)=5x+41 equation:


Simplifying
(3x + 19) + (2x + 22) = 5x + 41

Reorder the terms:
(19 + 3x) + (2x + 22) = 5x + 41

Remove parenthesis around (19 + 3x)
19 + 3x + (2x + 22) = 5x + 41

Reorder the terms:
19 + 3x + (22 + 2x) = 5x + 41

Remove parenthesis around (22 + 2x)
19 + 3x + 22 + 2x = 5x + 41

Reorder the terms:
19 + 22 + 3x + 2x = 5x + 41

Combine like terms: 19 + 22 = 41
41 + 3x + 2x = 5x + 41

Combine like terms: 3x + 2x = 5x
41 + 5x = 5x + 41

Reorder the terms:
41 + 5x = 41 + 5x

Add '-41' to each side of the equation.
41 + -41 + 5x = 41 + -41 + 5x

Combine like terms: 41 + -41 = 0
0 + 5x = 41 + -41 + 5x
5x = 41 + -41 + 5x

Combine like terms: 41 + -41 = 0
5x = 0 + 5x
5x = 5x

Add '-5x' to each side of the equation.
5x + -5x = 5x + -5x

Combine like terms: 5x + -5x = 0
0 = 5x + -5x

Combine like terms: 5x + -5x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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