(3x+18)+(9x+27)=99

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Solution for (3x+18)+(9x+27)=99 equation: 



(3x+18)+(9x+27)=99

We move all terms to the left:

(3x+18)+(9x+27)-(99)=0

We get rid of parentheses

3x+9x+18+27-99=0

We add all the numbers together, and all the variables

12x-54=0

We move all terms containing x to the left, all other terms to the right

12x=54

x=54/12

x=4+1/2

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