(3x+17)=(2x-4)+(5x+17)

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Solution for (3x+17)=(2x-4)+(5x+17) equation: 



(3x+17)=(2x-4)+(5x+17)

We move all terms to the left:

(3x+17)-((2x-4)+(5x+17))=0

We get rid of parentheses

3x-((2x-4)+(5x+17))+17=0



We calculate terms in parentheses: -((2x-4)+(5x+17)), so:

(2x-4)+(5x+17)

We get rid of parentheses

2x+5x-4+17

We add all the numbers together, and all the variables

7x+13

Back to the equation:

-(7x+13)



We get rid of parentheses

3x-7x-13+17=0

We add all the numbers together, and all the variables

-4x+4=0

We move all terms containing x to the left, all other terms to the right

-4x=-4

x=-4/-4

x=1

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