(3x+17)=(10x-5)+(3x+2)

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Solution for (3x+17)=(10x-5)+(3x+2) equation: 



(3x+17)=(10x-5)+(3x+2)

We move all terms to the left:

(3x+17)-((10x-5)+(3x+2))=0

We get rid of parentheses

3x-((10x-5)+(3x+2))+17=0



We calculate terms in parentheses: -((10x-5)+(3x+2)), so:

(10x-5)+(3x+2)

We get rid of parentheses

10x+3x-5+2

We add all the numbers together, and all the variables

13x-3

Back to the equation:

-(13x-3)



We get rid of parentheses

3x-13x+3+17=0

We add all the numbers together, and all the variables

-10x+20=0

We move all terms containing x to the left, all other terms to the right

-10x=-20

x=-20/-10

x=+2

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