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(3x+16/7)+(x+28/4)=12
We move all terms to the left:
(3x+16/7)+(x+28/4)-(12)=0
We add all the numbers together, and all the variables
(+3x+16/7)+(x+7)-12=0
We get rid of parentheses
3x+x+7-12+16/7=0
We multiply all the terms by the denominator
3x*7+x*7+16+7*7-12*7=0
We add all the numbers together, and all the variables
3x*7+x*7-19=0
Wy multiply elements
21x+7x-19=0
We add all the numbers together, and all the variables
28x-19=0
We move all terms containing x to the left, all other terms to the right
28x=19
x=19/28
x=19/28
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