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(3x+16)+(8x+3)=(10x-28)
We move all terms to the left:
(3x+16)+(8x+3)-((10x-28))=0
We get rid of parentheses
3x+8x-((10x-28))+16+3=0
We calculate terms in parentheses: -((10x-28)), so:We add all the numbers together, and all the variables
(10x-28)
We get rid of parentheses
10x-28
Back to the equation:
-(10x-28)
11x-(10x-28)+19=0
We get rid of parentheses
11x-10x+28+19=0
We add all the numbers together, and all the variables
x+47=0
We move all terms containing x to the left, all other terms to the right
x=-47
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