(3x+15)=(4x-12)

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Solution for (3x+15)=(4x-12) equation: 



(3x+15)=(4x-12)

We move all terms to the left:

(3x+15)-((4x-12))=0

We get rid of parentheses

3x-((4x-12))+15=0



We calculate terms in parentheses: -((4x-12)), so:

(4x-12)

We get rid of parentheses

4x-12

Back to the equation:

-(4x-12)



We get rid of parentheses

3x-4x+12+15=0

We add all the numbers together, and all the variables

-1x+27=0

We move all terms containing x to the left, all other terms to the right

-x=-27

x=-27/-1

x=+27

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