(3x+14)+(5x-2)=(10x-18)=

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Solution for (3x+14)+(5x-2)=(10x-18)= equation: 



(3x+14)+(5x-2)=(10x-18)=

We move all terms to the left:

(3x+14)+(5x-2)-((10x-18))=0

We get rid of parentheses

3x+5x-((10x-18))+14-2=0



We calculate terms in parentheses: -((10x-18)), so:

(10x-18)

We get rid of parentheses

10x-18

Back to the equation:

-(10x-18)



We add all the numbers together, and all the variables

8x-(10x-18)+12=0

We get rid of parentheses

8x-10x+18+12=0

We add all the numbers together, and all the variables

-2x+30=0

We move all terms containing x to the left, all other terms to the right

-2x=-30

x=-30/-2

x=+15

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