(3x+14)+(2x+8)=(7x-2)

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Solution for (3x+14)+(2x+8)=(7x-2) equation: 



(3x+14)+(2x+8)=(7x-2)

We move all terms to the left:

(3x+14)+(2x+8)-((7x-2))=0

We get rid of parentheses

3x+2x-((7x-2))+14+8=0



We calculate terms in parentheses: -((7x-2)), so:

(7x-2)

We get rid of parentheses

7x-2

Back to the equation:

-(7x-2)



We add all the numbers together, and all the variables

5x-(7x-2)+22=0

We get rid of parentheses

5x-7x+2+22=0

We add all the numbers together, and all the variables

-2x+24=0

We move all terms containing x to the left, all other terms to the right

-2x=-24

x=-24/-2

x=+12

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