(3x+13)=83+(x+10)

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Solution for (3x+13)=83+(x+10) equation: 



(3x+13)=83+(x+10)

We move all terms to the left:

(3x+13)-(83+(x+10))=0

We get rid of parentheses

3x-(83+(x+10))+13=0



We calculate terms in parentheses: -(83+(x+10)), so:

83+(x+10)

determiningTheFunctionDomain
(x+10)+83

We get rid of parentheses

x+10+83

We add all the numbers together, and all the variables

x+93

Back to the equation:

-(x+93)



We get rid of parentheses

3x-x-93+13=0

We add all the numbers together, and all the variables

2x-80=0

We move all terms containing x to the left, all other terms to the right

2x=80

x=80/2

x=40

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