(3x+13)=4(x-2)

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Solution for (3x+13)=4(x-2) equation: 



(3x+13)=4(x-2)

We move all terms to the left:

(3x+13)-(4(x-2))=0

We get rid of parentheses

3x-(4(x-2))+13=0



We calculate terms in parentheses: -(4(x-2)), so:

4(x-2)

We multiply parentheses

4x-8

Back to the equation:

-(4x-8)



We get rid of parentheses

3x-4x+8+13=0

We add all the numbers together, and all the variables

-1x+21=0

We move all terms containing x to the left, all other terms to the right

-x=-21

x=-21/-1

x=+21

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