(3x+12)=(6x+15)

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Solution for (3x+12)=(6x+15) equation: 



(3x+12)=(6x+15)

We move all terms to the left:

(3x+12)-((6x+15))=0

We get rid of parentheses

3x-((6x+15))+12=0



We calculate terms in parentheses: -((6x+15)), so:

(6x+15)

We get rid of parentheses

6x+15

Back to the equation:

-(6x+15)



We get rid of parentheses

3x-6x-15+12=0

We add all the numbers together, and all the variables

-3x-3=0

We move all terms containing x to the left, all other terms to the right

-3x=3

x=3/-3

x=-1

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