(3x+12)=(2x+18)

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Solution for (3x+12)=(2x+18) equation: 



(3x+12)=(2x+18)

We move all terms to the left:

(3x+12)-((2x+18))=0

We get rid of parentheses

3x-((2x+18))+12=0



We calculate terms in parentheses: -((2x+18)), so:

(2x+18)

We get rid of parentheses

2x+18

Back to the equation:

-(2x+18)



We get rid of parentheses

3x-2x-18+12=0

We add all the numbers together, and all the variables

x-6=0

We move all terms containing x to the left, all other terms to the right

x=6

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