(3x+12)-29x=57x+208-(5x+38)

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Solution for (3x+12)-29x=57x+208-(5x+38) equation: 



(3x+12)-29x=57x+208-(5x+38)

We move all terms to the left:

(3x+12)-29x-(57x+208-(5x+38))=0

We add all the numbers together, and all the variables

-29x+(3x+12)-(57x+208-(5x+38))=0

We get rid of parentheses

-29x+3x-(57x+208-(5x+38))+12=0



We calculate terms in parentheses: -(57x+208-(5x+38)), so:

57x+208-(5x+38)

determiningTheFunctionDomain
57x-(5x+38)+208

We get rid of parentheses

57x-5x-38+208

We add all the numbers together, and all the variables

52x+170

Back to the equation:

-(52x+170)



We add all the numbers together, and all the variables

-26x-(52x+170)+12=0

We get rid of parentheses

-26x-52x-170+12=0

We add all the numbers together, and all the variables

-78x-158=0

We move all terms containing x to the left, all other terms to the right

-78x=158

x=158/-78

x=-2+1/39

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