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(3x+12)(5x-40)=0
We multiply parentheses ..
(+15x^2-120x+60x-480)=0
We get rid of parentheses
15x^2-120x+60x-480=0
We add all the numbers together, and all the variables
15x^2-60x-480=0
a = 15; b = -60; c = -480;
Δ = b2-4ac
Δ = -602-4·15·(-480)
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{32400}=180$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-180}{2*15}=\frac{-120}{30} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+180}{2*15}=\frac{240}{30} =8 $
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