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(3x+12)(2x-18)=0
We multiply parentheses ..
(+6x^2-54x+24x-216)=0
We get rid of parentheses
6x^2-54x+24x-216=0
We add all the numbers together, and all the variables
6x^2-30x-216=0
a = 6; b = -30; c = -216;
Δ = b2-4ac
Δ = -302-4·6·(-216)
Δ = 6084
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6084}=78$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-78}{2*6}=\frac{-48}{12} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+78}{2*6}=\frac{108}{12} =9 $
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