(3x+11)=(x+4)+(7x-18)

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Solution for (3x+11)=(x+4)+(7x-18) equation: 



(3x+11)=(x+4)+(7x-18)

We move all terms to the left:

(3x+11)-((x+4)+(7x-18))=0

We get rid of parentheses

3x-((x+4)+(7x-18))+11=0



We calculate terms in parentheses: -((x+4)+(7x-18)), so:

(x+4)+(7x-18)

We get rid of parentheses

x+7x+4-18

We add all the numbers together, and all the variables

8x-14

Back to the equation:

-(8x-14)



We get rid of parentheses

3x-8x+14+11=0

We add all the numbers together, and all the variables

-5x+25=0

We move all terms containing x to the left, all other terms to the right

-5x=-25

x=-25/-5

x=+5

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