(3x+11)+(7x-5)+(9x-16)=180

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Solution for (3x+11)+(7x-5)+(9x-16)=180 equation: 



(3x+11)+(7x-5)+(9x-16)=180

We move all terms to the left:

(3x+11)+(7x-5)+(9x-16)-(180)=0

We get rid of parentheses

3x+7x+9x+11-5-16-180=0

We add all the numbers together, and all the variables

19x-190=0

We move all terms containing x to the left, all other terms to the right

19x=190

x=190/19

x=10

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