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(3x+11)(4x+8)=180
We move all terms to the left:
(3x+11)(4x+8)-(180)=0
We multiply parentheses ..
(+12x^2+24x+44x+88)-180=0
We get rid of parentheses
12x^2+24x+44x+88-180=0
We add all the numbers together, and all the variables
12x^2+68x-92=0
a = 12; b = 68; c = -92;
Δ = b2-4ac
Δ = 682-4·12·(-92)
Δ = 9040
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9040}=\sqrt{16*565}=\sqrt{16}*\sqrt{565}=4\sqrt{565}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(68)-4\sqrt{565}}{2*12}=\frac{-68-4\sqrt{565}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(68)+4\sqrt{565}}{2*12}=\frac{-68+4\sqrt{565}}{24} $
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