(3x+100)=(7x+20)

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Solution for (3x+100)=(7x+20) equation: 



(3x+100)=(7x+20)

We move all terms to the left:

(3x+100)-((7x+20))=0

We get rid of parentheses

3x-((7x+20))+100=0



We calculate terms in parentheses: -((7x+20)), so:

(7x+20)

We get rid of parentheses

7x+20

Back to the equation:

-(7x+20)



We get rid of parentheses

3x-7x-20+100=0

We add all the numbers together, and all the variables

-4x+80=0

We move all terms containing x to the left, all other terms to the right

-4x=-80

x=-80/-4

x=+20

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