(3x+10)+47=(9x-39)

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Solution for (3x+10)+47=(9x-39) equation: 



(3x+10)+47=(9x-39)

We move all terms to the left:

(3x+10)+47-((9x-39))=0

We get rid of parentheses

3x-((9x-39))+10+47=0



We calculate terms in parentheses: -((9x-39)), so:

(9x-39)

We get rid of parentheses

9x-39

Back to the equation:

-(9x-39)



We add all the numbers together, and all the variables

3x-(9x-39)+57=0

We get rid of parentheses

3x-9x+39+57=0

We add all the numbers together, and all the variables

-6x+96=0

We move all terms containing x to the left, all other terms to the right

-6x=-96

x=-96/-6

x=+16

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