(3x+1)=(x+19)

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Solution for (3x+1)=(x+19) equation: 



(3x+1)=(x+19)

We move all terms to the left:

(3x+1)-((x+19))=0

We get rid of parentheses

3x-((x+19))+1=0



We calculate terms in parentheses: -((x+19)), so:

(x+19)

We get rid of parentheses

x+19

Back to the equation:

-(x+19)



We get rid of parentheses

3x-x-19+1=0

We add all the numbers together, and all the variables

2x-18=0

We move all terms containing x to the left, all other terms to the right

2x=18

x=18/2

x=9

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