(3x+1)=(8x-10)

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Solution for (3x+1)=(8x-10) equation: 



(3x+1)=(8x-10)

We move all terms to the left:

(3x+1)-((8x-10))=0

We get rid of parentheses

3x-((8x-10))+1=0



We calculate terms in parentheses: -((8x-10)), so:

(8x-10)

We get rid of parentheses

8x-10

Back to the equation:

-(8x-10)



We get rid of parentheses

3x-8x+10+1=0

We add all the numbers together, and all the variables

-5x+11=0

We move all terms containing x to the left, all other terms to the right

-5x=-11

x=-11/-5

x=2+1/5

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