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(3x+1)=(8x+1)
We move all terms to the left:
(3x+1)-((8x+1))=0
We get rid of parentheses
3x-((8x+1))+1=0
We calculate terms in parentheses: -((8x+1)), so:We get rid of parentheses
(8x+1)
We get rid of parentheses
8x+1
Back to the equation:
-(8x+1)
3x-8x-1+1=0
We add all the numbers together, and all the variables
-5x=0
x=0/-5
x=0
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