(3x+1)2+(x+2)2=65

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Solution for (3x+1)2+(x+2)2=65 equation: 



(3x+1)2+(x+2)2=65

We move all terms to the left:

(3x+1)2+(x+2)2-(65)=0

We multiply parentheses

6x+2x+2+4-65=0

We add all the numbers together, and all the variables

8x-59=0

We move all terms containing x to the left, all other terms to the right

8x=59

x=59/8

x=7+3/8

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