(3x+1)/8=(5+2x)/7+2

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Solution for (3x+1)/8=(5+2x)/7+2 equation: 


x in (-oo:+oo)

(3*x+1)/8 = (2*x+5)/7+2 // - (2*x+5)/7+2

(3*x+1)/8-((2*x+5)/7)-2 = 0

(3*x+1)/8+(-1*(2*x+5))/7-2 = 0

(7*(3*x+1))/(7*8)+(-1*8*(2*x+5))/(7*8)+(-2*7*8)/(7*8) = 0

7*(3*x+1)-1*8*(2*x+5)-2*7*8 = 0

5*x-112-33 = 0

5*x-145 = 0

(5*x-145)/(7*8) = 0

(5*x-145)/(7*8) = 0 // * 7*8

5*x-145 = 0

5*x-145 = 0 // + 145

5*x = 145 // : 5

x = 145/5

x = 29

x = 29

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