(3x+1)/2=(2x+9)/3

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Solution for (3x+1)/2=(2x+9)/3 equation:



(3x+1)/2=(2x+9)/3
We move all terms to the left:
(3x+1)/2-((2x+9)/3)=0
We calculate fractions
3x/()+(-((2x+9)*2)/()=0
We calculate terms in parentheses: +(-((2x+9)*2)/(), so:
-((2x+9)*2)/(
We multiply all the terms by the denominator
-((2x+9)*2)
We calculate terms in parentheses: -((2x+9)*2), so:
(2x+9)*2
We multiply parentheses
4x+18
Back to the equation:
-(4x+18)
We get rid of parentheses
-4x-18
Back to the equation:
+(-4x-18)
We get rid of parentheses
3x/()-4x-18=0
We multiply all the terms by the denominator
3x-4x*()-18*()=0
We add all the numbers together, and all the variables
3x-4x*()=0

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