(3x+1)+(4x-5)=8x-9

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Solution for (3x+1)+(4x-5)=8x-9 equation:


Simplifying
(3x + 1) + (4x + -5) = 8x + -9

Reorder the terms:
(1 + 3x) + (4x + -5) = 8x + -9

Remove parenthesis around (1 + 3x)
1 + 3x + (4x + -5) = 8x + -9

Reorder the terms:
1 + 3x + (-5 + 4x) = 8x + -9

Remove parenthesis around (-5 + 4x)
1 + 3x + -5 + 4x = 8x + -9

Reorder the terms:
1 + -5 + 3x + 4x = 8x + -9

Combine like terms: 1 + -5 = -4
-4 + 3x + 4x = 8x + -9

Combine like terms: 3x + 4x = 7x
-4 + 7x = 8x + -9

Reorder the terms:
-4 + 7x = -9 + 8x

Solving
-4 + 7x = -9 + 8x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8x' to each side of the equation.
-4 + 7x + -8x = -9 + 8x + -8x

Combine like terms: 7x + -8x = -1x
-4 + -1x = -9 + 8x + -8x

Combine like terms: 8x + -8x = 0
-4 + -1x = -9 + 0
-4 + -1x = -9

Add '4' to each side of the equation.
-4 + 4 + -1x = -9 + 4

Combine like terms: -4 + 4 = 0
0 + -1x = -9 + 4
-1x = -9 + 4

Combine like terms: -9 + 4 = -5
-1x = -5

Divide each side by '-1'.
x = 5

Simplifying
x = 5

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