(3x+1)(3x+1)=(8x-4)

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Solution for (3x+1)(3x+1)=(8x-4) equation: 



(3x+1)(3x+1)=(8x-4)

We move all terms to the left:

(3x+1)(3x+1)-((8x-4))=0

We multiply parentheses ..

(+9x^2+3x+3x+1)-((8x-4))=0



We calculate terms in parentheses: -((8x-4)), so:

(8x-4)

We get rid of parentheses

8x-4

Back to the equation:

-(8x-4)



We get rid of parentheses

9x^2+3x+3x-8x+1+4=0

We add all the numbers together, and all the variables

9x^2-2x+5=0

a = 9; b = -2; c = +5;
Δ = b2-4ac
Δ = -22-4·9·5
Δ = -176
Delta is less than zero, so there is no solution for the equation

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