(3x+1)(2x-1)=11x-7

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Solution for (3x+1)(2x-1)=11x-7 equation:


Simplifying
(3x + 1)(2x + -1) = 11x + -7

Reorder the terms:
(1 + 3x)(2x + -1) = 11x + -7

Reorder the terms:
(1 + 3x)(-1 + 2x) = 11x + -7

Multiply (1 + 3x) * (-1 + 2x)
(1(-1 + 2x) + 3x * (-1 + 2x)) = 11x + -7
((-1 * 1 + 2x * 1) + 3x * (-1 + 2x)) = 11x + -7
((-1 + 2x) + 3x * (-1 + 2x)) = 11x + -7
(-1 + 2x + (-1 * 3x + 2x * 3x)) = 11x + -7
(-1 + 2x + (-3x + 6x2)) = 11x + -7

Combine like terms: 2x + -3x = -1x
(-1 + -1x + 6x2) = 11x + -7

Reorder the terms:
-1 + -1x + 6x2 = -7 + 11x

Solving
-1 + -1x + 6x2 = -7 + 11x

Solving for variable 'x'.

Reorder the terms:
-1 + 7 + -1x + -11x + 6x2 = -7 + 11x + 7 + -11x

Combine like terms: -1 + 7 = 6
6 + -1x + -11x + 6x2 = -7 + 11x + 7 + -11x

Combine like terms: -1x + -11x = -12x
6 + -12x + 6x2 = -7 + 11x + 7 + -11x

Reorder the terms:
6 + -12x + 6x2 = -7 + 7 + 11x + -11x

Combine like terms: -7 + 7 = 0
6 + -12x + 6x2 = 0 + 11x + -11x
6 + -12x + 6x2 = 11x + -11x

Combine like terms: 11x + -11x = 0
6 + -12x + 6x2 = 0

Factor out the Greatest Common Factor (GCF), '6'.
6(1 + -2x + x2) = 0

Factor a trinomial.
6((1 + -1x)(1 + -1x)) = 0

Ignore the factor 6.

Subproblem 1

Set the factor '(1 + -1x)' equal to zero and attempt to solve: Simplifying 1 + -1x = 0 Solving 1 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1x = 0 + -1 -1x = 0 + -1 Combine like terms: 0 + -1 = -1 -1x = -1 Divide each side by '-1'. x = 1 Simplifying x = 1

Subproblem 2

Set the factor '(1 + -1x)' equal to zero and attempt to solve: Simplifying 1 + -1x = 0 Solving 1 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1x = 0 + -1 -1x = 0 + -1 Combine like terms: 0 + -1 = -1 -1x = -1 Divide each side by '-1'. x = 1 Simplifying x = 1

Solution

x = {1, 1}

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