(3x+1)(2-x)=0

Solution for (3x+1)(2-x)=0 equation:

(3x+1)(2-x)=0

We add all the numbers together, and all the variables

(3x+1)(-1x+2)=0

We multiply parentheses ..

(-3x^2+6x-1x+2)=0

We get rid of parentheses

-3x^2+6x-1x+2=0

We add all the numbers together, and all the variables

-3x^2+5x+2=0

a = -3; b = 5; c = +2;
Δ = b2-4ac
Δ = 52-4·(-3)·2
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-7}{2*-3}=\frac{-12}{-6}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+7}{2*-3}=\frac{2}{-6}
=-1/3
$