(3x+1)(1-3x)=0

Solution for (3x+1)(1-3x)=0 equation:

Simplifying
(3x + 1)(1 + -3x) = 0

Reorder the terms:
(1 + 3x)(1 + -3x) = 0

Multiply (1 + 3x) * (1 + -3x)
(1(1 + -3x) + 3x * (1 + -3x)) = 0
((1 * 1 + -3x * 1) + 3x * (1 + -3x)) = 0
((1 + -3x) + 3x * (1 + -3x)) = 0
(1 + -3x + (1 * 3x + -3x * 3x)) = 0
(1 + -3x + (3x + -9x2)) = 0

Combine like terms: -3x + 3x = 0
(1 + 0 + -9x2) = 0
(1 + -9x2) = 0

Solving
1 + -9x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -9x2 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -9x2 = 0 + -1
-9x2 = 0 + -1

Combine like terms: 0 + -1 = -1
-9x2 = -1

Divide each side by '-9'.
x2 = 0.1111111111

Simplifying
x2 = 0.1111111111

Take the square root of each side:
x = {-0.333333333, 0.333333333}