(3x+(-5))/2=11

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Solution for (3x+(-5))/2=11 equation: 



(3x+(-5))/2=11

We move all terms to the left:

(3x+(-5))/2-(11)=0

We multiply all the terms by the denominator


(3x+(-5))-11*2=0



We calculate terms in parentheses: +(3x+(-5)), so:

3x+(-5)

We add all the numbers together, and all the variables

3x-5

Back to the equation:

+(3x-5)



We add all the numbers together, and all the variables

(3x-5)-22=0

We get rid of parentheses

3x-5-22=0

We add all the numbers together, and all the variables

3x-27=0

We move all terms containing x to the left, all other terms to the right

3x=27

x=27/3

x=9

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