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(3x)/x=x/400
We move all terms to the left:
(3x)/x-(x/400)=0
Domain of the equation: x!=0We add all the numbers together, and all the variables
x∈R
3x/x-(+x/400)=0
We get rid of parentheses
3x/x-x/400=0
We calculate fractions
(-1x^2)/400x+1200x/400x=0
We multiply all the terms by the denominator
(-1x^2)+1200x=0
We get rid of parentheses
-1x^2+1200x=0
a = -1; b = 1200; c = 0;
Δ = b2-4ac
Δ = 12002-4·(-1)·0
Δ = 1440000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1440000}=1200$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1200)-1200}{2*-1}=\frac{-2400}{-2} =+1200 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1200)+1200}{2*-1}=\frac{0}{-2} =0 $
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