(3x)/4=(1-x)/12

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Solution for (3x)/4=(1-x)/12 equation: 



(3x)/4=(1-x)/12

We move all terms to the left:

(3x)/4-((1-x)/12)=0

We add all the numbers together, and all the variables

3x/4-((-1x+1)/12)=0

We calculate fractions


36x^2/()+(-((-1x+1)*4)/()=0



We calculate terms in parentheses: +(-((-1x+1)*4)/(), so:

-((-1x+1)*4)/(

We multiply all the terms by the denominator


-((-1x+1)*4)



We calculate terms in parentheses: -((-1x+1)*4), so:

(-1x+1)*4

We multiply parentheses

-4x+4

Back to the equation:

-(-4x+4)



We get rid of parentheses

4x-4

Back to the equation:

+(4x-4)



We get rid of parentheses

36x^2/()+4x-4=0

We multiply all the terms by the denominator


36x^2+4x*()-4*()=0

We add all the numbers together, and all the variables

36x^2+4x*()=0

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