(3x)/(x+2)-4=2/(x+2)

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Solution for (3x)/(x+2)-4=2/(x+2) equation: 



(3x)/(x+2)-4=2/(x+2)

We move all terms to the left:

(3x)/(x+2)-4-(2/(x+2))=0



Domain of the equation: (x+2)!=0

We move all terms containing x to the left, all other terms to the right

x!=-2

x∈R





Domain of the equation: (x+2))!=0

x∈R



We calculate fractions


9x^2/((x+2)*(x+2)))+(-(2*(x+2))/((x+2)*(x+2)))-4=0

We calculate fractions


(9x^2*((x+2)*(x+2)))-4)/(((x+2)*(x+2)))+(*((x+2)*(x+2)))-4)+(-(2*(x+2))*((x+2)*(x+2)))+()/(((x+2)*(x+2)))+(*((x+2)*(x+2)))-4)=0



We calculate terms in parentheses: +(9x^2*((x+2)*(x+2))), so:

9x^2*((x+2)*(x+2))



We can not solve this equation

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